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45t^2-125=0
a = 45; b = 0; c = -125;
Δ = b2-4ac
Δ = 02-4·45·(-125)
Δ = 22500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{22500}=150$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-150}{2*45}=\frac{-150}{90} =-1+2/3 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+150}{2*45}=\frac{150}{90} =1+2/3 $
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